(a+b)(a^3-3ab-b^2)=0

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Solution for (a+b)(a^3-3ab-b^2)=0 equation: 


Simplifying
(a + b)(a3 + -3ab + -1b2) = 0

Reorder the terms:
(a + b)(-3ab + a3 + -1b2) = 0

Multiply (a + b) * (-3ab + a3 + -1b2)
(a(-3ab + a3 + -1b2) + b(-3ab + a3 + -1b2)) = 0
((-3ab * a + a3 * a + -1b2 * a) + b(-3ab + a3 + -1b2)) = 0

Reorder the terms:
((-1ab2 + -3a2b + a4) + b(-3ab + a3 + -1b2)) = 0
((-1ab2 + -3a2b + a4) + b(-3ab + a3 + -1b2)) = 0
(-1ab2 + -3a2b + a4 + (-3ab * b + a3 * b + -1b2 * b)) = 0
(-1ab2 + -3a2b + a4 + (-3ab2 + a3b + -1b3)) = 0

Reorder the terms:
(-1ab2 + -3ab2 + -3a2b + a3b + a4 + -1b3) = 0

Combine like terms: -1ab2 + -3ab2 = -4ab2
(-4ab2 + -3a2b + a3b + a4 + -1b3) = 0

Solving
-4ab2 + -3a2b + a3b + a4 + -1b3 = 0

Solving for variable 'a'.

The solution to this equation could not be determined.

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